Optimal. Leaf size=91 \[ \frac{\left (8 a^2+8 a b+3 b^2\right ) \tan ^{-1}(\sinh (c+d x))}{8 d}-\frac{3 b (2 a+b) \tanh (c+d x) \text{sech}(c+d x)}{8 d}-\frac{b \tanh (c+d x) \text{sech}^3(c+d x) \left ((a+b) \sinh ^2(c+d x)+a\right )}{4 d} \]
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Rubi [A] time = 0.085125, antiderivative size = 91, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {3676, 413, 385, 203} \[ \frac{\left (8 a^2+8 a b+3 b^2\right ) \tan ^{-1}(\sinh (c+d x))}{8 d}-\frac{3 b (2 a+b) \tanh (c+d x) \text{sech}(c+d x)}{8 d}-\frac{b \tanh (c+d x) \text{sech}^3(c+d x) \left ((a+b) \sinh ^2(c+d x)+a\right )}{4 d} \]
Antiderivative was successfully verified.
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Rule 3676
Rule 413
Rule 385
Rule 203
Rubi steps
\begin{align*} \int \text{sech}(c+d x) \left (a+b \tanh ^2(c+d x)\right )^2 \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+(a+b) x^2\right )^2}{\left (1+x^2\right )^3} \, dx,x,\sinh (c+d x)\right )}{d}\\ &=-\frac{b \text{sech}^3(c+d x) \left (a+(a+b) \sinh ^2(c+d x)\right ) \tanh (c+d x)}{4 d}+\frac{\operatorname{Subst}\left (\int \frac{a (4 a+b)+(a+b) (4 a+3 b) x^2}{\left (1+x^2\right )^2} \, dx,x,\sinh (c+d x)\right )}{4 d}\\ &=-\frac{3 b (2 a+b) \text{sech}(c+d x) \tanh (c+d x)}{8 d}-\frac{b \text{sech}^3(c+d x) \left (a+(a+b) \sinh ^2(c+d x)\right ) \tanh (c+d x)}{4 d}+\frac{\left (8 a^2+8 a b+3 b^2\right ) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\sinh (c+d x)\right )}{8 d}\\ &=\frac{\left (8 a^2+8 a b+3 b^2\right ) \tan ^{-1}(\sinh (c+d x))}{8 d}-\frac{3 b (2 a+b) \text{sech}(c+d x) \tanh (c+d x)}{8 d}-\frac{b \text{sech}^3(c+d x) \left (a+(a+b) \sinh ^2(c+d x)\right ) \tanh (c+d x)}{4 d}\\ \end{align*}
Mathematica [C] time = 7.22038, size = 427, normalized size = 4.69 \[ -\frac{\text{csch}^3(c+d x) \left (128 \sinh ^6(c+d x) \left (a^2 \left (5 \sinh ^4(c+d x)+12 \sinh ^2(c+d x)+7\right )+2 a b \left (5 \sinh ^2(c+d x)+6\right ) \sinh ^2(c+d x)+5 b^2 \sinh ^4(c+d x)\right ) \text{HypergeometricPFQ}\left (\left \{\frac{3}{2},2,2,2\right \},\left \{1,1,\frac{9}{2}\right \},-\sinh ^2(c+d x)\right )+128 \sinh ^6(c+d x) \left (a \sinh ^2(c+d x)+a+b \sinh ^2(c+d x)\right )^2 \text{HypergeometricPFQ}\left (\left \{\frac{3}{2},2,2,2,2\right \},\left \{1,1,1,\frac{9}{2}\right \},-\sinh ^2(c+d x)\right )+35 \left (a^2 \left (485 \sinh ^6(c+d x)+3161 \sinh ^4(c+d x)+5907 \sinh ^2(c+d x)+3375\right )+2 a b \left (485 \sinh ^4(c+d x)+2554 \sinh ^2(c+d x)+2625\right ) \sinh ^2(c+d x)+b^2 \left (485 \sinh ^2(c+d x)+1947\right ) \sinh ^4(c+d x)\right )-\frac{105 \tanh ^{-1}\left (\sqrt{-\sinh ^2(c+d x)}\right ) \left (a^2 \left (9 \sinh ^8(c+d x)+400 \sinh ^6(c+d x)+1674 \sinh ^4(c+d x)+2344 \sinh ^2(c+d x)+1125\right )+2 a b \left (9 \sinh ^6(c+d x)+389 \sinh ^4(c+d x)+1143 \sinh ^2(c+d x)+875\right ) \sinh ^2(c+d x)+b^2 \left (9 \sinh ^4(c+d x)+378 \sinh ^2(c+d x)+649\right ) \sinh ^4(c+d x)\right )}{\sqrt{-\sinh ^2(c+d x)}}\right )}{6720 d} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.036, size = 173, normalized size = 1.9 \begin{align*} 2\,{\frac{{a}^{2}\arctan \left ({{\rm e}^{dx+c}} \right ) }{d}}-2\,{\frac{ab\sinh \left ( dx+c \right ) }{d \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}}+{\frac{ab{\rm sech} \left (dx+c\right )\tanh \left ( dx+c \right ) }{d}}+2\,{\frac{ab\arctan \left ({{\rm e}^{dx+c}} \right ) }{d}}-{\frac{{b}^{2} \left ( \sinh \left ( dx+c \right ) \right ) ^{3}}{d \left ( \cosh \left ( dx+c \right ) \right ) ^{4}}}-{\frac{{b}^{2}\sinh \left ( dx+c \right ) }{d \left ( \cosh \left ( dx+c \right ) \right ) ^{4}}}+{\frac{{b}^{2}\tanh \left ( dx+c \right ) \left ({\rm sech} \left (dx+c\right ) \right ) ^{3}}{4\,d}}+{\frac{3\,{b}^{2}{\rm sech} \left (dx+c\right )\tanh \left ( dx+c \right ) }{8\,d}}+{\frac{3\,{b}^{2}\arctan \left ({{\rm e}^{dx+c}} \right ) }{4\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.61505, size = 269, normalized size = 2.96 \begin{align*} -\frac{1}{4} \, b^{2}{\left (\frac{3 \, \arctan \left (e^{\left (-d x - c\right )}\right )}{d} + \frac{5 \, e^{\left (-d x - c\right )} - 3 \, e^{\left (-3 \, d x - 3 \, c\right )} + 3 \, e^{\left (-5 \, d x - 5 \, c\right )} - 5 \, e^{\left (-7 \, d x - 7 \, c\right )}}{d{\left (4 \, e^{\left (-2 \, d x - 2 \, c\right )} + 6 \, e^{\left (-4 \, d x - 4 \, c\right )} + 4 \, e^{\left (-6 \, d x - 6 \, c\right )} + e^{\left (-8 \, d x - 8 \, c\right )} + 1\right )}}\right )} - 2 \, a b{\left (\frac{\arctan \left (e^{\left (-d x - c\right )}\right )}{d} + \frac{e^{\left (-d x - c\right )} - e^{\left (-3 \, d x - 3 \, c\right )}}{d{\left (2 \, e^{\left (-2 \, d x - 2 \, c\right )} + e^{\left (-4 \, d x - 4 \, c\right )} + 1\right )}}\right )} + \frac{a^{2} \arctan \left (\sinh \left (d x + c\right )\right )}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.19051, size = 3433, normalized size = 37.73 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (a + b \tanh ^{2}{\left (c + d x \right )}\right )^{2} \operatorname{sech}{\left (c + d x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.39557, size = 212, normalized size = 2.33 \begin{align*} \frac{{\left (8 \, a^{2} e^{c} + 8 \, a b e^{c} + 3 \, b^{2} e^{c}\right )} \arctan \left (e^{\left (d x + c\right )}\right ) e^{\left (-c\right )} - \frac{8 \, a b e^{\left (7 \, d x + 7 \, c\right )} + 5 \, b^{2} e^{\left (7 \, d x + 7 \, c\right )} + 8 \, a b e^{\left (5 \, d x + 5 \, c\right )} - 3 \, b^{2} e^{\left (5 \, d x + 5 \, c\right )} - 8 \, a b e^{\left (3 \, d x + 3 \, c\right )} + 3 \, b^{2} e^{\left (3 \, d x + 3 \, c\right )} - 8 \, a b e^{\left (d x + c\right )} - 5 \, b^{2} e^{\left (d x + c\right )}}{{\left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right )}^{4}}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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